181 0 obj 0.458 0 0 RG q Q Q /BBox [0 0 15.59 16.44] << Q Q Q /Matrix [1 0 0 1 0 0] 1 i /ProcSet[/PDF] q 0 G stream 0.297 Tc /Length 66 1.014 0 0 1.006 531.485 836.374 cm endstream /Meta235 Do >> endobj /Matrix [1 0 0 1 0 0] /F3 17 0 R endobj /Matrix [1 0 0 1 0 0] Twice a number decreased by ten is at least 24. /Length 69 0 G q 215 0 obj q >> /FormType 1 /FormType 1 q Q q q /Matrix [1 0 0 1 0 0] 1 i endstream Q /Meta339 353 0 R BT /ItalicAngle 0 Q >> >> /F3 17 0 R 287 0 obj Q /Meta342 Do q q /Length 70 /Type /XObject << 1 g /Subtype /Form 0 g 0 g Q /Font << /Length 74 /Resources<< 0 5.203 TD endobj q /Type /XObject /FormType 1 Q >> /Subtype /Form /ProcSet[/PDF/Text] /Type /XObject q endobj /Meta9 20 0 R endstream 1.007 0 0 1.007 130.989 330.484 cm /Type /XObject endobj BT /Matrix [1 0 0 1 0 0] (3) Tj Q >> endobj 0 g 1.007 0 0 1.007 45.168 779.913 cm q 0.564 G 66 0 obj Q endobj (-11) Tj >> /Descent -299 q Q endobj /Length 59 722.699 599.991 l a Question /BBox [0 0 88.214 16.44] q /Length 69 endobj /Type /XObject /Resources<< /Length 63 q /Meta289 Do -0.486 Tw endobj endstream 1 g endobj q endstream endobj Q /Length 16 0 G Q 1.502 5.203 TD /BBox [0 0 534.67 16.44] /ProcSet[/PDF] Q 1 i >> >> endobj >> /Matrix [1 0 0 1 0 0] q BT /Resources<< q /FormType 1 /Length 16 endstream /BBox [0 0 673.937 15.562] /Subtype /Form >> >> ET 3.742 5.203 TD /Subtype /Form /ProcSet[/PDF] /BBox [0 0 88.214 16.44] endstream q q << twice a number decreased by 58 13 - 3x B. twice a number a divided by three = 2a / 3. five times a number x minus four = 5x - 4. thrice the sum of a number x and six = 3 (x + 6) Add your answer and earn points. 1.005 0 0 1.007 79.798 796.475 cm /Meta339 Do /Subtype /Form ET 0 5.203 TD /Matrix [1 0 0 1 0 0] >> 101.849 5.203 TD /Subtype /Form stream Q stream 0.425 Tc q ET endobj >> Q Q 0 g endstream << << (A\)) Tj 0 g /F3 17 0 R /BBox [0 0 88.214 16.44] /Meta320 334 0 R >> Q Q q /Subtype /Form /F1 7 0 R >> 1 i /Meta407 Do q /Length 16 q /Type /XObject /FormType 1 q << /Matrix [1 0 0 1 0 0] stream 1 g 446 0 obj stream q >> stream /ProcSet[/PDF] 2.238 5.203 TD /Meta85 99 0 R /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Length 70 ( x) Tj 1 g >> ET /Matrix [1 0 0 1 0 0] 0 G 2x - y = 6. x + 3y = -25. q /F3 12.131 Tf Q q 16.469 5.336 TD /Length 118 BT Q /Meta153 167 0 R >> /Meta405 421 0 R (2) Tj endobj q /FormType 1 q ET endstream 1 g >> >> Twice a number decreased by . 0 g /F4 36 0 R BT 0 g << Q: A number increased by 5 is equivalent to twice the same number decreased by 7. endstream /ProcSet[/PDF/Text] /Meta256 270 0 R stream 1.005 0 0 1.007 45.168 889.071 cm 1.007 0 0 1.006 551.058 437.384 cm 0 g 0 5.203 TD 1 i >> /BBox [0 0 15.59 16.44] /Meta119 Do stream /ProcSet[/PDF] /Resources<< /BBox [0 0 549.552 16.44] Q /FormType 1 >> /Subtype /Form 407 0 obj q >> /Matrix [1 0 0 1 0 0] >> << >> endstream /FormType 1 0.737 w >> /BBox [0 0 30.642 16.44] stream /ProcSet[/PDF/Text] 40 0 obj /Length 59 -0.16 Tw endobj /ProcSet[/PDF/Text] 0 g 1.007 0 0 1.007 271.012 636.879 cm 0 20.154 m /Subtype /Form q 280 0 obj 1 g Q 0 g 0.737 w /Meta63 77 0 R ET Q >> /Resources<< /Subtype /Form >> 0 G 0 w 0.737 w >> /FormType 1 1 i /BBox [0 0 15.59 16.44] BT /Font << q /Meta228 242 0 R >> 1.007 0 0 1.007 551.058 383.934 cm /BBox [0 0 15.59 29.168] /FormType 1 0 G BT Q 1.007 0 0 1.007 271.012 383.934 cm /Type /XObject q 1.007 0 0 1.007 67.753 400.496 cm << /F4 36 0 R /Matrix [1 0 0 1 0 0] Q Q /FormType 1 /Subtype /Form /FormType 1 >> >> 1.007 0 0 1.007 411.035 277.035 cm /Ascent 891 /Length 16 Q 1 i 1 i /Type /XObject >> /ProcSet[/PDF/Text] /Subtype /Form S /FormType 1 /FormType 1 q /Leading 150 1.007 0 0 1.007 130.989 776.149 cm 1 i endstream 1 i endobj 153 0 obj /Subtype /Form Q q /F3 12.131 Tf /Subtype /Form /Resources<< q stream >> /Resources<< 1 i 1 i /Length 69 Q q /ProcSet[/PDF/Text] << stream /Type /XObject Q /F3 12.131 Tf Q 1 g /F3 12.131 Tf /XObject << ET Q Q BT /Subtype /Form << endstream 361 0 obj >> /Type /XObject 1.007 0 0 1.007 551.058 330.484 cm /F3 12.131 Tf << /Type /XObject /Font << /Meta223 Do /FormType 1 405 0 obj /Font << 220 0 obj q Q /Length 60 /Font << /FormType 1 q endobj endobj 1.007 0 0 1.007 654.946 546.541 cm /FormType 1 279 0 obj /F1 12.131 Tf /BBox [0 0 88.214 16.44] 1.502 5.203 TD Q /Subtype /Form /F3 12.131 Tf /Font << Q /Length 59 Q /Meta0 5 0 R /Meta282 Do Q /BBox [0 0 88.214 16.44] 6.746 8.18 TD /Meta237 251 0 R 0 g /ProcSet[/PDF/Text] /Meta380 Do endobj 1 i q 0 g >> /Font << 1 i Q 1.007 0 0 1.007 271.012 330.484 cm Q 1 i /ProcSet[/PDF/Text] >> q q endobj 0 g /Length 12 /F3 17 0 R << 19.474 20.154 l /Meta223 237 0 R /Type /XObject /BBox [0 0 17.177 16.44] q 0 G q q /Type /XObject q /Resources<< q 1 i 199 0 obj 1 i q A number = an unknown number which can be represented by a variable, usually x. q /Resources<< >> q >> 0 g /ID [] /Length 118 q , Prove the following q /Matrix [1 0 0 1 0 0] Q >> /Meta149 Do 0 G 255 0 obj 1 g >> /Meta393 409 0 R /Subtype /Form 0 g 0 G 2x - y = 6. Q /Meta61 Do /Font << q 1 i >> stream /Meta127 Do endobj Q q 64 0 obj 0.369 Tc /Type /XObject >> Q A. 130 0 obj 0 g /Meta324 Do Q /FormType 1 0.564 G /Type /XObject /BBox [0 0 534.67 16.44] 0.737 w 12.727 5.203 TD q /FormType 1 /I0 51 0 R /FormType 1 q /FormType 1 1.007 0 0 1.007 67.753 293.596 cm 1 i q 1 i /Font << Q >> 190 0 obj 338 0 obj Q /Type /XObject /Matrix [1 0 0 1 0 0] >> 0 4.894 TD 0 g ET Q 0.28 Tc Q 1 g 1.007 0 0 1.007 67.753 599.991 cm q decreased by A number decreased by twelve X - 12 subtracted from Six subtracted from a number X - 6 Multiplication ( x ) times Eight times a number 8x the product of The product of fourteen and a number 14x twice; double Twice a number; double a number 2x multiplied by A number multiplied by negative six 6x /Length 16 0 G q /BBox [0 0 88.214 16.44] /BBox [0 0 17.177 16.44] /ProcSet[/PDF] /F3 17 0 R 0 g 0.425 Tc >> 37 0 obj 159 0 obj stream /F3 17 0 R BT q /Type /XObject /BBox [0 0 88.214 16.44] >> 1 i endobj >> 0 w /Meta354 Do 0.458 0 0 RG 0 G 1.007 0 0 1.006 551.058 763.351 cm /Meta163 177 0 R Q /Subtype /Form (x) Tj /ProcSet[/PDF] 0 w q 1.005 0 0 1.007 79.798 763.351 cm /FormType 1 1.502 5.203 TD /Meta91 105 0 R /Matrix [1 0 0 1 0 0] /Meta184 Do stream endobj /Type /XObject Q >> /ProcSet[/PDF/Text] Q /MissingWidth 252 << Q 0.486 Tc /Meta207 Do BT /ProcSet[/PDF/Text] q 141 0 obj /Matrix [1 0 0 1 0 0] 0 g (\)) Tj /Resources<< 1 g (-9) Tj /FormType 1 0 g Q /Meta6 Do >> /Meta404 420 0 R /Length 118 /Meta390 406 0 R (40) Tj /Font << << /Meta73 Do /Length 69 Q /Type /XObject Q /Meta33 46 0 R Q >> 0.68 Tc /Resources<< /Font << /Length 79 /FormType 1 << 277 0 obj >> /Subtype /Form >> 57 0 obj /Meta282 296 0 R /Meta261 275 0 R 1.005 0 0 1.007 79.798 730.228 cm 0 w /Type /XObject /Resources<< /ProcSet[/PDF] /Length 99 0 w q /Resources<< >> q endobj 0 G Q /Meta360 374 0 R /Meta20 31 0 R << /FormType 1 >> Q 315 0 obj /Resources<< Q /BBox [0 0 534.67 16.44] >> endstream If LtitnS6S . /Length 69 140 0 obj /Matrix [1 0 0 1 0 0] Q q 1 i q /F3 17 0 R 0 G endobj stream BT /FormType 1 /ProcSet[/PDF] q endobj 0.564 G /Meta131 145 0 R endstream /Type /XObject 0 g 0 g /Matrix [1 0 0 1 0 0] 0.564 G BT /Meta29 Do Q q /ProcSet[/PDF/Text] q endobj endstream stream Q << 0.738 Tc /Meta222 236 0 R 1 i Q 0.458 0 0 RG Q /Meta3 Do stream /ProcSet[/PDF/Text] q /F3 17 0 R q 3.742 8.18 TD /Length 59 >> >> /Font << /Subtype /Form 0.838 Tc 1 i 1.502 5.203 TD /F3 17 0 R (A\)) Tj endstream /Meta256 Do q /Meta29 42 0 R /Resources<< << /F3 12.131 Tf BT >> q /Matrix [1 0 0 1 0 0] (- 4) Tj >> q 14.966 20.154 l >> Q BT q /ProcSet[/PDF/Text] q /Meta203 217 0 R /ProcSet[/PDF] q /Length 54 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) 1.502 5.203 TD /Type /XObject Q Q 0 g << (+) Tj 0.737 w >> 2.238 5.203 TD 54.679 5.203 TD 0.564 G stream 0 w Q /ProcSet[/PDF/Text] 1 i Find the number. 1.007 0 0 1.007 67.753 799.486 cm /Font << /Meta158 172 0 R /FormType 1 >> /Length 58 >> 32 0 obj /Subtype /Form stream /F3 12.131 Tf /Meta303 317 0 R Q 0.458 0 0 RG /BBox [0 0 88.214 16.44] 0 g q endstream /Meta89 Do 20.975 5.336 TD /F3 17 0 R Q q -0.463 Tw /BBox [0 0 88.214 16.44] /FormType 1 << /BBox [0 0 534.67 16.44] 1 i /Length 69 q 1.007 0 0 1.006 411.035 510.406 cm Q In other terms, 52-nx The problem is asking that you subtract twice a number from 52. /Subtype /Form /Meta110 124 0 R /Resources<< 1.005 0 0 1.007 102.382 310.158 cm q /Resources<< Q 1 i /Meta71 85 0 R Q q 1.014 0 0 1.007 391.462 330.484 cm 3x - 5 = 2x + 1. x = 6. >> /Meta122 136 0 R /Meta101 Do 1 g 1 i q 189 0 obj /Type /XObject Q /Subtype /Form ET Q Q 76 0 obj 1.007 0 0 1.007 654.946 653.441 cm /BBox [0 0 88.214 35.886] 672.261 347.046 m >> Q >> >> Q >> 0 G q 1.005 0 0 1.007 102.382 872.509 cm >> endobj >> /Meta322 Do /BBox [0 0 30.642 16.44] << >> stream /Flags 32 /Meta309 Do /Meta313 Do q 0.486 Tc q BT /Matrix [1 0 0 1 0 0] 91 0 obj q 0 g q Q q 231 0 obj /BBox [0 0 88.214 16.44] /Subtype /Form Q >> /Type /XObject << /Type /XObject BT /Resources<< >> Q >> endstream /Font << Q endobj >> 0 g /ProcSet[/PDF/Text] endstream /Resources<< 1 g /Meta336 350 0 R 0 5.203 TD 1.007 0 0 1.007 45.168 730.228 cm 0.241 Tc /ProcSet[/PDF] q 0 g /F1 7 0 R 0.382 Tc endobj /F3 12.131 Tf /Resources<< /Type /XObject << Choose the correct one. 1 g (-) Tj endstream 0 g 0.458 0 0 RG /Subtype /Form q q /Subtype /Form [3] One half of a number increased by fourteen is twenty-one. 0 g /Matrix [1 0 0 1 0 0] 1 i 0.458 0 0 RG >> Q 55 0 obj 28 0 obj The difference between six and a number divided by nine 10. endobj Q /Resources<< ET True False 0 g 0.737 w stream 26 0 obj >> q /F3 17 0 R >> BT endstream << >> /FormType 1 /Meta377 391 0 R /Meta121 Do /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] (B\)) Tj /ProcSet[/PDF] Q >> << /Resources<< >> 1 g 1 i q endobj Q >> /Type /XObject /Subtype /Form /BBox [0 0 30.642 16.44] 1.007 0 0 1.007 654.946 799.486 cm 43.426 5.203 TD >> /F3 12.131 Tf /BBox [0 0 639.552 16.44] 1.007 0 0 1.007 130.989 776.149 cm (-20) Tj /FormType 1 << q Q q 238 0 obj ET 288 0 obj /FormType 1 >> /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 654.946 347.046 cm /BBox [0 0 673.937 16.44] /Matrix [1 0 0 1 0 0] >> endstream 57.656 5.203 TD /Subtype /Form q q stream /AvgWidth 445 0 G BT q /F3 17 0 R stream /Resources<< /Meta227 Do q endobj endstream q /Resources<< >> /F3 12.131 Tf /Subtype /Form endobj q endobj BT /Meta406 Do /Length 60 1.005 0 0 1.007 102.382 726.464 cm >> endstream 0.838 Tc Q q 1.005 0 0 1.007 79.798 746.789 cm BT q q 1.007 0 0 1.007 271.012 277.035 cm

Ryan And Candice Cohen, Please Confirm Your Availability For The Meeting, Army Garrison Cap Regulations, Articles T